Week 1 Problem E
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Week 1 Problem E
There are three candidates, Al, Bill, and Charlie. Bill has at least onefifth the number of votes Charlie has, and has at most onethird the number of votes Al has. If the sum of Bill and Charlie's votes is at least 600, what is the least votes Al can get?
Archis Admin
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Re: Week 1 Problem E
workin on it............ill post my solution later.
Mira Holford The Cool Cube
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Re: Week 1 Problem E
My solution:
 Spoiler:
 300 is my answer.
Bill + Charlie is greater than or equal to 600.
Bill is greater than or equal to 1/5 of Charlie's votes, but less than 1/3 of Al's votes.
Now since we want the least for Al, imagine as if all the inequalities were all equal signs. Thus we have B+C= 600; B= (1/5)C; B= (1/3)A
Substituting into the first equation, you get (6/5)C= 600 or C=500
With C=500, therefore B is 100.
With B=100, the least Al could be, by the third equation, is 3B or 300.
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Re: Week 1 Problem E
wow your good archis!
Steve The Cool Cube
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Re: Week 1 Problem E
Steve wrote:wow your good archis!
I KNOW!!!!!!!!!!!!
Mira Holford The Cool Cube
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