Week 3 Problem F
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Week 3 Problem F
Theo made an elaborate code to remember the 10digit combination to his bicycle lock. This is the code he came up with: AKBJCHDGEF. In his code, each letter stands for a different digit (09). To find the combination, use the clues below to figure out what digit is represented by each letter. When two letters are written together without an operation symbol, they represent a tens digit and a ones digit.
D + D + D = F
B / H = K
H + H = B
D x H = CK
G + B + E = F + A + C
A x H = KE
J + A = CC
J / D = K
F x D = KG
D / J = H/B
What is the 10digit combination to Theo's bicycle lock?
A quick note to problem solvers: I do not write these problems and will post the answers once given to me.
D + D + D = F
B / H = K
H + H = B
D x H = CK
G + B + E = F + A + C
A x H = KE
J + A = CC
J / D = K
F x D = KG
D / J = H/B
What is the 10digit combination to Theo's bicycle lock?
A quick note to problem solvers: I do not write these problems and will post the answers once given to me.
Archis Admin
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Re: Week 3 Problem F
Archis wrote:
D + D + D = F
B / H = K
H + H = B
D x H = CK
G + B + E = F + A + C
A x H = KE
J + A = CC
J / D = K
F x D = KG
D / J = H/B
My answer
 Spoiler:
 5286143709
Explanation:
 Spoiler:
 since J+A=CC, C has to be one. F has to be 6, or 9 because D+D+D=F. and D can't be one because C is 1. Then D has to be 2, or 3. FxD=KG so KG is either 12 or 27. KG cant be 12 because C is already one so K is 2 and G is 7. Then F is 9 and D is 3. Since J/D=K, J/3=2 so J is 6. DxH is CK so 3xH=12 so H is 4. H+H is B so B is 8. J+A=CC so 6+A=11 so A is 5. AxH=KE so 5x4=2E so E is 0. The Final answer is AKBJCHDGEF or 5286143709
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