Zillian and Zillo
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What is your answer?
Zillian and Zillo
Zillian tosses one penny and Zillo tosses two pennies. The probability that Zillo gets the same number of head that Zillian gets is what common fraction?
A) 1/4
B) 3/8
C) 1/2
D) 2/3
E) 3/4
I'll post the solution after a significant number of replies.
A) 1/4
B) 3/8
C) 1/2
D) 2/3
E) 3/4
I'll post the solution after a significant number of replies.
Re: Zillian and Zillo
Um.. 1/4.. because.... they need better names...
I'll actually try the problem in a bit.
I'll actually try the problem in a bit.
Ben R- LogarithmLover
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Re: Zillian and Zillo
What kind of names are zillian and zillo? anyway i don't even get how to do the problem. I might try it later, but for now
Steve- The Cool Cube
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Re: Zillian and Zillo
Steve wrote:What kind of names are zillian and zillo? anyway i don't even get how to do the problem. I might try it later, but for now
ya i know
Mira Holford- The Cool Cube
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Re: Zillian and Zillo
how do u do the poll thingy?
Steve- The Cool Cube
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Re: Zillian and Zillo
idk but archis will come and tell us the answer
Mira Holford- The Cool Cube
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Re: Zillian and Zillo
When you post a new topic, if you scroll down, you'll see poll options. You can take it from there.
Ben R- LogarithmLover
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Re: Zillian and Zillo
Ben R wrote:When you post a new topic, if you scroll down, you'll see poll options. You can take it from there.
ohhhhhhhhhhhhhh
Mira Holford- The Cool Cube
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Re: Zillian and Zillo
Archis wrote:Zillian tosses one penny and Zillo tosses two pennies. The probability that Zillo gets the same number of head that Zillian gets is what common fraction?
Probability is equal to # of successes/total possibilities. Note this is a very easy probability question if the successes is approached with proper casework.
Case I: They each throw 0 heads
- Spoiler:
There is only 1 result that corresponds to this case
Zillo: TT
Zillian: T
- Spoiler:
- .
There are two possible results
Zillo: HT, TH
Zillian: H
Combining both the results from Case I and II, you get 3 successes. In total there are 8 possibilities (3 coins are being tossed for 2*2*2.)
#successes/#possibilities = 3/8
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